Given two independent sets I and J of a graph G, imagine that a token (coin) is placed on each vertex in I. Then, the Sliding Token problem asks if one could transforms I to J using a sequence of elementary steps, where each step requires sliding a token from one vertex to one of its neighbors, such that the resulting set of vertices where tokens are placed still remains independent. In this paper, we describe a polynomial-time algorithm for solving Sliding Token in case the graph G is a cactus. Our algorithm is designed based on two observations. First, all structures that forbid the existence of a sequence of token slidings between I and J, if exist, can be found in polynomial time. A no-instance may be easily deduced using this characterization. Second, without such forbidden structures, a sequence of token slidings between I and J does exist.
@InProceedings{hoang_et_al:LIPIcs.ISAAC.2016.37, author = {Hoang, Duc A. and Uehara, Ryuhei}, title = {{Sliding Tokens on a Cactus}}, booktitle = {27th International Symposium on Algorithms and Computation (ISAAC 2016)}, pages = {37:1--37:26}, series = {Leibniz International Proceedings in Informatics (LIPIcs)}, ISBN = {978-3-95977-026-2}, ISSN = {1868-8969}, year = {2016}, volume = {64}, editor = {Hong, Seok-Hee}, publisher = {Schloss Dagstuhl -- Leibniz-Zentrum f{\"u}r Informatik}, address = {Dagstuhl, Germany}, URL = {https://drops.dagstuhl.de/entities/document/10.4230/LIPIcs.ISAAC.2016.37}, URN = {urn:nbn:de:0030-drops-68074}, doi = {10.4230/LIPIcs.ISAAC.2016.37}, annote = {Keywords: reconfiguration problem, token sliding, independent set, cactus} }
Feedback for Dagstuhl Publishing