# [LeetCode]#1491. Average Salary Excluding the Minimum and Maximum Salary

**Environment: Python 3.8**

**Key technique: remove**

Given an array of **unique** integers `salary`

where `salary[i]`

is the salary of the employee `i`

.

Return the average salary of employees excluding the minimum and maximum salary.

**Example 1:**

**Input:** salary = [4000,3000,1000,2000]

**Output:** 2500.00000

**Explanation: **Minimum salary and maximum salary are 1000 and 4000 respectively.

Average salary excluding minimum and maximum salary is (2000+3000)/2= 2500

**Example 2:**

**Input:** salary = [1000,2000,3000]

**Output:** 2000.00000

**Explanation: **Minimum salary and maximum salary are 1000 and 3000 respectively.

Average salary excluding minimum and maximum salary is (2000)/1= 2000

**Example 3:**

**Input:** salary = [6000,5000,4000,3000,2000,1000]

**Output:** 3500.00000

**Example 4:**

**Input:** salary = [8000,9000,2000,3000,6000,1000]

**Output:** 4750.00000

**Analysis:**

- remove min and max number.
- Calculate average.

**Solution:**

`class Solution:`

def average(self, salary):

salary.remove(max(salary))

salary.remove(min(salary))

return (sum(salary)/len(salary))

**Submissions:**

**Reference:**